Figure 3 shows a lamp connected to a d.c - Edexcel - GCSE Physics - Question 2 - 2022 - Paper 1

To calculate the power supplied to the lamp, we can use several formulations. One common equation is:

$\text{power} = V \times I$

Substituting the known values:

$\text{power} = 4.5 \text{ V} \times 0.30 \text{ A} = 1.35 \text{ W}$

Alternatively, we can also calculate power using resistance:

$\text{power} = \frac{V^2}{R}$

We already determined R as 15 Ω, so:

$\text{power} = \frac{(4.5 \text{ V})^2}{15 \Omega} = 1.35 \text{ W}$

In conclusion, the power supplied to the lamp is 1.35 W.