A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

The power supplied to the lamp can be calculated using the formula:

$P = V \times I$

Substituting the known values:

$P = 6.0 \, \text{V} \times 0.40 \, \text{A} = 2.4 \, \text{W}$

Therefore, the power supplied is 2.4 W.

The energy transferred by the lamp can be calculated using the formula:

$E = P \times t$

where:

• $E$ is the energy,
• $P$ is the power, and
• $t$ is the time in seconds.

Substituting the known values:

$E = 2.4 \, \text{W} \times 40 \, \text{s} = 96 \, \text{J}$

Thus, the energy transferred by the lamp in 40 seconds is 96 J.