This question is about using the mains electricity supply - Edexcel - GCSE Physics - Question 5 - 2021 - Paper 1

To calculate the energy transferred, we can use the formula: $E = I \times V \times t$ where:

• I is the current (7.4 A)
• V is the voltage (230 V)
• t is the time (120 s)

Substituting the values: $E = 7.4 \times 230 \times 120 = 204240 J$ Thus, the energy transferred to the coffee machine in 120 seconds is 200,000 J.

Wire X is the neutral wire, and wire Y is the live wire.

Component Z is the fuse.

For the transformer, we can use the formula: $\text{input current} \times \text{input voltage} = \text{output current} \times \text{output voltage}$

Rearranging for input current gives us: $\text{input current} = \frac{\text{output current} \times \text{output voltage}}{\text{input voltage}}$ Substituting the values: $\text{input current} = \frac{2.37 \times 190}{230} \approx 1.89 A$ The input current to the transformer is approximately 1.89 A.