The particles of a gas exert a pressure on the walls of a container - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1
Question 4
The particles of a gas exert a pressure on the walls of a container.
Which row of the table is correct when the pressure of the gas changes?
| pressure of gas | num... show full transcript
Worked Solution & Example Answer:The particles of a gas exert a pressure on the walls of a container - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1
Step 1
Which row of the table is correct when the pressure of the gas changes?
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Answer
The correct row is:
A: increases
B: increases
C: decreases
D: decreases
The pressure of the gas increases as the number of particles colliding with the walls of the container increases. Therefore, the answer is A.
Step 2
Calculate the value of this temperature in kelvin.
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Answer
To convert from Celsius to Kelvin, use the formula:
K=°C+273.15
Thus, for 23°C:
K=23+273.15=296.15K
Therefore, the value in kelvin is approximately 296.15 K.
Step 3
Identify the anomalous result plotted on Figure 7 by drawing a circle on Figure 7 around the anomalous point.
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Answer
The anomalous point is identified at the volume of 12 ml with a pressure reading of 200 kPa, which deviates from the established trend of the other data points.
Step 4
Draw the curve of best fit on Figure 7.
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Answer
The curve of best fit should be a smooth curve touching as many points as possible while indicating the relationship between volume and pressure, emphasizing the negative correlation as volume increases, pressure decreases.
Step 5
Describe how the graph in Figure 7 would change if the student repeated the experiment with the same mass of gas, at a higher constant temperature.
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Answer
If the student repeats the experiment at a higher constant temperature, all data points would shift higher on the pressure axis, leading to a higher curve on the graph, while maintaining a similar shape. This indicates that at higher temperatures, for the same volume, the pressure will be greater.
Step 6
Calculate the pressure, P2, in the large balloon.
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Answer
Using the equation:
P1V1=P2V2
Substituting the values:
8.00extMPaimes14.5extcm3=P2imes1160extcm3P2 = rac{8.00 imes 14.5}{1160}
Calculating:
P2ext(inMPa)=0.099extMPa
Thus, the pressure in the large balloon, P2, is approximately 0.099 MPa.