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The particles of a gas exert a pressure on the walls of a container - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1

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The particles of a gas exert a pressure on the walls of a container. Which row of the table is correct when the pressure of the gas changes? | pressure of gas | num... show full transcript

Worked Solution & Example Answer:The particles of a gas exert a pressure on the walls of a container - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1

Step 1

Which row of the table is correct when the pressure of the gas changes?

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Answer

The correct row is:

  • A: increases
  • B: increases
  • C: decreases
  • D: decreases The pressure of the gas increases as the number of particles colliding with the walls of the container increases. Therefore, the answer is A.

Step 2

Calculate the value of this temperature in kelvin.

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Answer

To convert from Celsius to Kelvin, use the formula: K=°C+273.15K = °C + 273.15 Thus, for 23°C: K=23+273.15=296.15KK = 23 + 273.15 = 296.15 K Therefore, the value in kelvin is approximately 296.15 K.

Step 3

Identify the anomalous result plotted on Figure 7 by drawing a circle on Figure 7 around the anomalous point.

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Answer

The anomalous point is identified at the volume of 12 ml with a pressure reading of 200 kPa, which deviates from the established trend of the other data points.

Step 4

Draw the curve of best fit on Figure 7.

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Answer

The curve of best fit should be a smooth curve touching as many points as possible while indicating the relationship between volume and pressure, emphasizing the negative correlation as volume increases, pressure decreases.

Step 5

Describe how the graph in Figure 7 would change if the student repeated the experiment with the same mass of gas, at a higher constant temperature.

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Answer

If the student repeats the experiment at a higher constant temperature, all data points would shift higher on the pressure axis, leading to a higher curve on the graph, while maintaining a similar shape. This indicates that at higher temperatures, for the same volume, the pressure will be greater.

Step 6

Calculate the pressure, P2, in the large balloon.

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Answer

Using the equation: P1V1=P2V2P1V1 = P2V2 Substituting the values: 8.00extMPaimes14.5extcm3=P2imes1160extcm38.00 ext{ MPa} imes 14.5 ext{ cm}^3 = P2 imes 1160 ext{ cm}^3 P2 = rac{8.00 imes 14.5}{1160} Calculating: P2ext(inMPa)=0.099extMPaP2 ext{ (in MPa)} = 0.099 ext{ MPa} Thus, the pressure in the large balloon, P2, is approximately 0.099 MPa.

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