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9 (a) An atom of mass 6.6 × 10^-28 kg is moving with a velocity of 480 m/s - Edexcel - GCSE Physics - Question 9 - 2023 - Paper 1
Question 9
9 (a) An atom of mass 6.6 × 10^-28 kg is moving with a velocity of 480 m/s. Calculate the momentum of the atom. (b) Figure 18 shows a ball before and after it colli... show full transcript
Worked Solution & Example Answer:9 (a) An atom of mass 6.6 × 10^-28 kg is moving with a velocity of 480 m/s - Edexcel - GCSE Physics - Question 9 - 2023 - Paper 1
Step 1
Calculate the momentum of the atom
Answer
To find the momentum ( P) of the atom, we can use the formula:
where:
- m is the mass of the atom (6.6 × 10^-28 kg)
- v is the velocity (480 m/s)
Substituting these values gives:
Calculating this results in:
Thus, the momentum of the atom is 3.2 × 10^-25 kg m/s.
Step 2
Calculate the force exerted on the ball by the wall
Answer
To find the force exerted on the ball by the wall, we first need to calculate the change in momentum ( ΔP) during the collision.
The initial momentum before collision, P_{initial} = 0.80 ext{ kg m/s}
The final momentum after collision, P_{final} = -0.60 ext{ kg m/s}
(The negative sign indicates the opposite direction)
Now we calculate the change in momentum:
Next, we determine the time of collision, which is given as 70 ms (or 0.070 s).
By using Newton's second law, the force (F) can be calculated as:
F = rac{ΔP}{Δt}
Substituting the values gives:
F = rac{-1.40 ext{ kg m/s}}{0.070 ext{ s}} = -20 ext{ N}
The negative sign indicates the direction of the force opposing the ball's motion. Therefore, the force exerted on the ball by the wall is 20 N.