Figure 19 shows a small piece of copper about 3 cm high - Edexcel - GCSE Physics - Question 8 - 2020 - Paper 1

The density of copper can be calculated using the formula:

ho = \frac{0.058}{6.5 \times 10^{-6}}\approx 8923.08 , kg/m^3$$

Thus, the density of copper is approximately $8923 \, kg/m^3$.

To find the specific heat capacity of copper, we can rearrange the equation for thermal energy:

$\Delta Q = m c \Delta \theta$

Where:

• $\,\Delta Q = 10500 \, J$ (thermal energy gained by water)
• $m = 0.058 \, kg$ (mass of copper)
• $\,\Delta \theta = 100 - 22 = 78 \, °C$ (temperature change)

Now substituting these into the rearranged formula:

$c = \frac{\Delta Q}{m \Delta \theta} = \frac{10500}{0.058 \times 78} \approx 230 \, J/kg \, °C$

Therefore, the specific heat capacity of copper is approximately $230 \, J/kg \, °C$.

1. Reduce heat loss from the water by insulating the beaker or covering it, which minimizes energy loss to the environment.
2. Use a more accurate method for measuring the temperature, such as a calibrated thermometer, to ensure precise measurements.

The coil can be used in place of the Bunsen burner by connecting it to a low voltage power supply, allowing it to heat up due to electrical resistance. This heating can then be used to warm the water in the beaker, providing a more controlled heating element compared to an open flame.