Photo AI

6 (a) Which of these would be a typical speed for a racing cyclist travelling down a steep straight slope? A 0.2 m/s B 2 m/s C 20 m/s D 200 m/s (iii) A cyclist travels down a slope - Edexcel - GCSE Physics - Question 6 - 2019 - Paper 1

Question icon

Question 6

6-(a)-Which-of-these-would-be-a-typical-speed-for-a-racing-cyclist-travelling-down-a-steep-straight-slope?---A--0.2-m/s-B--2-m/s-C--20-m/s-D--200-m/s--(iii)-A-cyclist-travels-down-a-slope-Edexcel-GCSE Physics-Question 6-2019-Paper 1.png

6 (a) Which of these would be a typical speed for a racing cyclist travelling down a steep straight slope? A 0.2 m/s B 2 m/s C 20 m/s D 200 m/s (iii) A cyclis... show full transcript

Worked Solution & Example Answer:6 (a) Which of these would be a typical speed for a racing cyclist travelling down a steep straight slope? A 0.2 m/s B 2 m/s C 20 m/s D 200 m/s (iii) A cyclist travels down a slope - Edexcel - GCSE Physics - Question 6 - 2019 - Paper 1

Step 1

Which of these would be a typical speed for a racing cyclist travelling down a steep straight slope?

96%

114 rated

Answer

To determine the typical speed for a racing cyclist on a steep slope, we need to consider realistic cycling speeds.

  • A speed of 0.2 m/s is too slow for a racing cyclist.
  • A speed of 2 m/s may be considered slow but could be feasible for certain conditions.
  • A speed of 20 m/s is more typical for a racing cyclist going downhill; however, it depends on the slope's steepness and the cyclist's skill.
  • Lastly, a speed of 200 m/s is unrealistic for a cyclist.

Thus, the answer is: C 20 m/s.

Step 2

Calculate the change in gravitational potential energy of the cyclist between the top and the bottom of the slope.

99%

104 rated

Answer

The formula for gravitational potential energy (GPE) is: ΔGPE=mgh\Delta GPE = m \cdot g \cdot h Where:

  • mm is the mass (75 kg)
  • gg is the gravitational field strength (10 N/kg)
  • hh is the height change (20 m)

Substituting the values: ΔGPE=751020\Delta GPE = 75 \cdot 10 \cdot 20

Calculating this gives: ΔGPE=15000 J\Delta GPE = 15000 \text{ J}

Thus, the change in gravitational potential energy is 15000 J.

Step 3

Calculate the distance, x, travelled by the aircraft while it is accelerating.

96%

101 rated

Answer

Given the initial speed u=0u = 0 m/s, final speed v=80v = 80 m/s, and acceleration a=4a = 4 m/s², we can use the equation: x=v2u22ax = \frac{v^{2} - u^{2}}{2a}

Substituting in the values: x=8020224x = \frac{80^{2} - 0^{2}}{2 \cdot 4} x=64008x = \frac{6400}{8} x=800extmx = 800 ext{ m}

Thus, the distance travelled by the aircraft is 800 m.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;