Photo AI

a) A motorcyclist is climbing a hill at a constant speed of 13 m/s - Edexcel - GCSE Physics - Question 3 - 2017 - Paper 1

Question icon

Question 3

a)-A-motorcyclist-is-climbing-a-hill-at-a-constant-speed-of-13-m/s-Edexcel-GCSE Physics-Question 3-2017-Paper 1.png

a) A motorcyclist is climbing a hill at a constant speed of 13 m/s. Calculate the time it takes for the motorcyclist to travel 29 m. (2) b) The picture shows a rai... show full transcript

Worked Solution & Example Answer:a) A motorcyclist is climbing a hill at a constant speed of 13 m/s - Edexcel - GCSE Physics - Question 3 - 2017 - Paper 1

Step 1

Calculate the time it takes for the motorcyclist to travel 29 m.

96%

114 rated

Answer

To find the time taken, we can use the formula:

t=dvt = \frac{d}{v}\,

where:

  • dd is the distance (29 m)
  • vv is the speed (13 m/s)

Substituting in the values:

t=2913 2.23st = \frac{29}{13} \ \approx 2.23 s\,

Since time cannot be negative, our final answer is approximately 2.23 seconds.

Step 2

Explain how this design makes good use of energy transfers in the system.

99%

104 rated

Answer

In the railway system described, the design utilizes gravitational potential energy effectively. When one passenger cabin descends, the gravitational potential energy of that cabin decreases, which in turn is converted into kinetic energy as it moves downwards. This kinetic energy is then transferred to the opposite cabin, which is lifted upwards. Thus, the system maintains a balance, as the energy lost by one cabin is gained by the other, showcasing efficient energy transfer and minimizing energy wastage.

Step 3

State the value of the kinetic energy of the car when the brakes were first applied.

96%

101 rated

Answer

The value of the kinetic energy (KE) of the car when the brakes were applied equals the work done to stop it, which is 510 000 J.

Step 4

Calculate the velocity of the car when the brakes were first applied.

98%

120 rated

Answer

To calculate the velocity, we can use the formula for kinetic energy:

KE=12mv2KE = \frac{1}{2}mv^2\,

where:

  • KEKE is the kinetic energy (510 000 J)
  • mm is the mass (1400 kg)

Rearranging the formula gives:

v=2KEmv = \sqrt{\frac{2 \cdot KE}{m}}\,

Substituting the values:

v=25100001400=730v = \sqrt{\frac{2 \cdot 510000}{1400}} = \sqrt{730}\,

Calculating this gives approximately:

v \approx 27 m/s\.

Step 5

Calculate the distance it takes for the brakes to stop the car.

97%

117 rated

Answer

Using the work-energy principle, the work done by the brakes to stop the car can be calculated using:

W=FdW = F \cdot d\,

where:

  • WW is the work done (510 000 J)
  • FF is the average force (15 000 N)
  • dd is the distance

Rearranging gives:

d=WFd = \frac{W}{F}\,

Substituting the values:

d = \frac{510000}{15000} = 34 m\.

Thus, the distance it takes for the brakes to stop the car is 34 meters.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;