An electrostatic air filter is designed to remove dust particles from the air in a room - Edexcel - GCSE Physics - Question 2 - 2015 - Paper 1
Question 2
An electrostatic air filter is designed to remove dust particles from the air in a room.
A fan blows dusty air past several metal rods and metal plates.
There is a l... show full transcript
Worked Solution & Example Answer:An electrostatic air filter is designed to remove dust particles from the air in a room - Edexcel - GCSE Physics - Question 2 - 2015 - Paper 1
Step 1
Complete the sentence by putting a cross (✗) in the box next to your answer.
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Answer
In the context of an electrostatic air filter, dust particles gain electrons from the negatively charged metal rods. Therefore, the correct completion for the sentence is 'C gain electrons'.
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Answer
The metal plates in the electrostatic air filter attract the dust particles because they possess an opposite charge. The dust particles become positively charged as they lose electrons and are attracted to the negatively charged plates due to electrostatic attraction.
Step 3
transferred to plate / lost
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Answer
The charge (electrons) is transferred to the metal plates from the dust particles, causing the dust to lose its electrons and thus become neutral or discharged.
Step 4
An explanation linking any two of - Metal is a conductor (1) - Electrons / (negative) charge moves (through the plates/wire) (1) - Towards the voltage supply / earth / ground (1)
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Answer
Metal is a conductor, which allows the movement of electrons. In the air filter, the electrons (negative charge) move from the dust particles to the plates, facilitating the attraction and removal of dust. These charges ultimately move towards the voltage supply or are earthed for grounding.
Step 5
Q = 1.2 x 10^3 x 48 (1)
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Answer
Using the formula for charge, we can calculate it as follows:
Q=1.2imes103imes48
This calculation results in a value of 57600 coulombs.
Step 6
Evaluation: 0.048 or 4.8 x 10^2 (1)
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Answer
After evaluating the charge, we can express it in proper coulomb units. The correct conversion will yield either 0.048 C or equivalent to 4.8 x 10^2 mC, where mC represents milliCoulombs.
