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This question is about using the mains electricity supply - Edexcel - GCSE Physics - Question 5 - 2021 - Paper 1

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This question is about using the mains electricity supply. (a) (i) An electric kettle is used to boil some water. The mains supply voltage is 230 V. The power supp... show full transcript

Worked Solution & Example Answer:This question is about using the mains electricity supply - Edexcel - GCSE Physics - Question 5 - 2021 - Paper 1

Step 1

Calculate the current in the kettle.

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Answer

To find the current (II) supplied to the kettle, we can use the formula:

I=PVI = \frac{P}{V}

Substituting the given values:

I=1.9×103W230VI = \frac{1.9 \times 10^3 \, \text{W}}{230 \, \text{V}}

Evaluating this gives:

I8.26AI \approx 8.26 \, \text{A}

Thus, the current supplied to the kettle is approximately 8.3 A.

Step 2

Calculate the energy transferred to the coffee machine in 120s.

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Answer

To calculate the energy transferred to the coffee machine, we use the formula:

E=I×V×tE = I \times V \times t

Where:

  • I=7.4AI = 7.4 \, \text{A}
  • V=230VV = 230 \, \text{V}
  • t=120st = 120 \, \text{s}

Substituting these values into the equation:

E=7.4×230×120E = 7.4 \times 230 \times 120

Evaluating gives:

E203,040JE \approx 203,040 \, \text{J}

Therefore, the energy transferred to the coffee machine is approximately 200,000 J.

Step 3

State the name of wire X and the name of wire Y.

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Answer

Wire X = neutral
Wire Y = live

Step 4

State the name of component Z.

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Answer

Component Z = fuse

Step 5

Calculate the input current to the transformer.

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Answer

To find the input current, we use the equation:

input current×input voltage=output current×output voltage\text{input current} \times \text{input voltage} = \text{output current} \times \text{output voltage}

Rearranging gives:

input current=output current×output voltageinput voltage\text{input current} = \frac{\text{output current} \times \text{output voltage}}{\text{input voltage}}

Substituting in the values:

input current=2.37A×190V230V\text{input current} = \frac{2.37 \, \text{A} \times 190 \, \text{V}}{230 \, \text{V}}

Calculating this yields:

input current1.95A\text{input current} \approx 1.95 \, \text{A}

Hence, the input current to the transformer is approximately 1.95 A.

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