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The particles of a gas exert a pressure on the walls of a container - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1

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The particles of a gas exert a pressure on the walls of a container. Which row of the table is correct when the pressure of the gas changes? | pressure of gas | num... show full transcript

Worked Solution & Example Answer:The particles of a gas exert a pressure on the walls of a container - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1

Step 1

Which row of the table is correct when the pressure of the gas changes?

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Answer

The correct row is A: when the pressure of the gas increases, the number of particles colliding with the walls of the container each second also increases.

Step 2

Calculate the value of this temperature in kelvin.

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Answer

To convert Celsius to Kelvin, we use the formula:

K=°C+273.15K = °C + 273.15

So, the temperature in Kelvin is:

K=23+273.15=296.15K = 23 + 273.15 = 296.15

Thus, the value is approximately 296 K.

Step 3

Identify the anomalous result plotted on Figure 7.

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Answer

The anomalous result can be identified at the data point for 12 ml and 200 kPa, which deviates from the trend.

Step 4

Draw the curve of best fit on Figure 7.

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Answer

The curve of best fit should touch as many points as possible without passing through the anomalous point, demonstrating the negative correlation between volume and pressure.

Step 5

Describe how the graph in Figure 7 would change if the student repeated the experiment.

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Answer

If the experiment were repeated with the same mass of gas at a higher temperature, the graph would shift upwards. Specifically, for the same volume, the pressure would be higher, leading to all points on the graph moving to a higher pressure value while maintaining a similar shape.

Step 6

Calculate the pressure, P₂, in the large balloon.

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Answer

Using the equation, we have:

P1V1=P2V2P₁V₁ = P₂V₂ Substituting the known values:

8.00extMPaimes14.5extcm3=P2imes1160extcm38.00 ext{ MPa} imes 14.5 ext{ cm}³ = P₂ imes 1160 ext{ cm}³

Solving for P₂:

P₂ = rac{8.00 imes 14.5}{1160}

Calculating gives us:

P2ext0.1MPaP₂ ext{ ≈ 0.1 MPa}

Thus, the pressure in the large balloon is approximately 0.1 MPa.

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