A free-fall parachutist is falling straight down - Edexcel - GCSE Physics - Question 5 - 2018 - Paper 1
Question 5
A free-fall parachutist is falling straight down.
This is a velocity/time graph of the first part of the jump, before the parachute is opened.
(a) Which of these po... show full transcript
Worked Solution & Example Answer:A free-fall parachutist is falling straight down - Edexcel - GCSE Physics - Question 5 - 2018 - Paper 1
Step 1
Which of these points on the graph shows the largest acceleration?
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Answer
To determine which point shows the largest acceleration, we need to examine the slope of the velocity-time graph. The acceleration is represented by the gradient (slope) of the graph. In this case:
Point A (0 to 5s): The slope is increasing but is mild.
Point B (5 to 10s): The slope is getting steeper, indicating increasing acceleration.
Point C (10 to 15s): The graph begins to plateau, indicating lesser acceleration.
Point D (15 to 30s): The slope is almost horizontal, indicating very low or no acceleration.
Thus, point B (Q) shows the largest acceleration, and the answer is B.
Step 2
Estimate the distance that the parachutist falls in the first 2.5 s.
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Answer
To estimate the distance fallen, we refer to the velocity-time graph. In the first 2.5 seconds (between points A and up to point B), we can calculate the distance as the area under the curve. The velocity at 2.5 seconds is approximately 12.5 m/s. Assuming constant acceleration:
The formula for distance is:
d=vt
Where:
d = distance,
v = average velocity,
t = time.
The average velocity for the first 2.5 seconds is approximately:
vavg=20+12.5=6.25extm/s
Thus, the estimated distance is:
d=6.25extm/s×2.5exts=15.625extm
Therefore, the parachutist falls approximately 16 meters in the first 2.5 seconds.