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9 (a) Which of these is a vector? A energy B force C mass D work (b) (i) State the equation that relates acceleration to change in velocity and time taken - Edexcel - GCSE Physics - Question 9 - 2020 - Paper 1

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9-(a)-Which-of-these-is-a-vector?---A--energy---B--force---C--mass---D--work----(b)-(i)-State-the-equation-that-relates-acceleration-to-change-in-velocity-and-time-taken-Edexcel-GCSE Physics-Question 9-2020-Paper 1.png

9 (a) Which of these is a vector? A energy B force C mass D work (b) (i) State the equation that relates acceleration to change in velocity and time t... show full transcript

Worked Solution & Example Answer:9 (a) Which of these is a vector? A energy B force C mass D work (b) (i) State the equation that relates acceleration to change in velocity and time taken - Edexcel - GCSE Physics - Question 9 - 2020 - Paper 1

Step 1

Which of these is a vector?

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Answer

The vector among the given options is B: force. A vector is a quantity that has both magnitude and direction, and force fits this definition.

Step 2

State the equation that relates acceleration to change in velocity and time taken.

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Answer

The equation that relates acceleration (a) to change in velocity (Δv) and time taken (t) is given by:

a=Δvta = \frac{\Delta v}{t}

where Δv is the change in velocity, calculated as the final velocity minus the initial velocity.

Step 3

Calculate the acceleration of the van.

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Answer

To calculate the acceleration of the van, we can use the formula:

a=Δvta = \frac{\Delta v}{t}

Where:

  • Initial velocity, vi=2v_i = 2 m/s
  • Final velocity, vf=20v_f = 20 m/s
  • Time, t=12t = 12 s

Calculating Δv:

Δv=vfvi=202=18 m/s\Delta v = v_f - v_i = 20 - 2 = 18 \text{ m/s}

Now, substituting into the equation:

a=18 m/s12 s=1.5 m/s2a = \frac{18 \text{ m/s}}{12 \text{ s}} = 1.5 \text{ m/s}^2.

Therefore, the acceleration of the van is 1.5 m/s².

Step 4

Calculate the distance the cyclist travels in the 15s.

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Answer

To calculate the distance traveled by the cyclist, we can find the area under the velocity-time graph. The graph forms a right triangle with:

  • Base (time) = 15 s
  • Height (velocity) = 7 m/s.

The formula for the area of a triangle is:

extArea=12×base×height ext{Area} = \frac{1}{2} \times \text{base} \times \text{height}

Calculating the area:

extArea=12×15 s×7 m/s=1052=52.5 m ext{Area} = \frac{1}{2} \times 15 \text{ s} \times 7 \text{ m/s} = \frac{105}{2} = 52.5 \text{ m}.

Thus, the distance the cyclist travels in 15 seconds is 52.5 m.

Step 5

Explain how the stopping distance of a car is affected by factors involving the driver.

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Answer

The stopping distance of a car can be significantly affected by several factors involving the driver:

  1. Reaction Time: A driver's reaction time (the time taken to respond to a hazard) can vary. A delayed reaction can increase the stopping distance.

  2. Tiredness: A tired driver may have slower reflexes, which can also delay their reaction time.

  3. Effect of Drugs: Use of drugs (both illegal and certain legal medications) can impair judgment and slow reaction times.

  4. Footwear: Inappropriate footwear can impede a driver's ability to operate the pedals effectively, potentially resulting in longer stopping distances.

These factors lead to an increased overall stopping distance due to either increased thinking/braking distance.

Step 6

Explain how the stopping distance of a car is affected by factors involving the car or the road.

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Answer

The stopping distance of a car is influenced by several factors related to either the car itself or the road conditions:

  1. Mass/Weight of the Car: Heavier vehicles require more distance to stop compared to lighter vehicles due to the greater inertia.

  2. State of Brakes: Worn or poorly maintained brakes can significantly affect stopping efficiency, increasing stopping distance.

  3. Tire Condition: Tires with insufficient tread or improper inflation can reduce grip, meaning the car takes longer to stop.

  4. State of the Road: Wet, icy, or poorly maintained roads can create hazardous conditions, increasing stopping distance due to reduced traction.

In summary, both driver behavior and vehicle/road conditions play crucial roles in determining stopping distance.

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