Figure 6 shows two objects, E and D. E emits a sound. D detects the sound. E is moving in the direction shown by the arrow, but D is not moving. E emits a sound of wavelength 1.86 m. D measures the wavelength of this sound as 1.98 m. (i) Calculate the difference between the wavelength that E emits and the wavelength that D detects.

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Figure 6 shows two objects, E and D - Edexcel - GCSE Physics - Question 4 - 2023 - Paper 1

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Figure 6 shows two objects, E and D. E emits a sound. D detects the sound. E is moving in the direction shown by the arrow, but D is not moving. E emits a sound of ... show full transcript

Worked Solution & Example Answer:Figure 6 shows two objects, E and D - Edexcel - GCSE Physics - Question 4 - 2023 - Paper 1

Step 1

Calculate the difference between the wavelengths

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Answer

To find the difference in wavelength, we use the formula:

$\Delta \lambda = \lambda_D - \lambda_E$

Where:

( \lambda_D ) is the wavelength measured by D (1.98 m)
( \lambda_E ) is the wavelength emitted by E (1.86 m)

Substituting the values:

$\Delta \lambda = 1.98 - 1.86$

$\Delta \lambda = 0.12 \text{ m}$

Thus, the difference in wavelength is 0.12 m.

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