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This question is about energy changes - Edexcel - GCSE Physics - Question 6 - 2021 - Paper 1

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This question is about energy changes. (a) Figure 11 shows a water slide. A person travels from the top to the bottom of the water slide. (i) The mass of the person... show full transcript

Worked Solution & Example Answer:This question is about energy changes - Edexcel - GCSE Physics - Question 6 - 2021 - Paper 1

Step 1

(i) The mass of the person, m = 72 kg. The change in vertical height, h = 7.0 m. Gravitational field strength, g = 10 N / kg. Calculate the change in gravitational potential energy for the person. Use the equation: change in gravitational potential energy = m × g × h

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Answer

To calculate the change in gravitational potential energy (GPE), we can use the formula:

ΔGPE=m×g×h\Delta GPE = m \times g \times h

Substituting the values:

ΔGPE=72 kg×10 N/kg×7.0 m\Delta GPE = 72 \text{ kg} \times 10 \text{ N/kg} \times 7.0 \text{ m}

Now, performing the calculation:

ΔGPE=72×10×7=5040 J\Delta GPE = 72 \times 10 \times 7 = 5040 \text{ J}

Thus, the change in gravitational potential energy for the person is 5040 J.

Step 2

(ii) The person comes to rest after the end of the water slide. Explain what happens to the energy as the person comes to rest after the end of the water slide.

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Answer

As the person comes to rest after exiting the water slide, the gravitational potential energy initially gained is transformed mainly into kinetic energy as they travel down the slide. However, upon reaching the end of the slide and coming to a rest, this kinetic energy is converted into other forms of energy, primarily thermal energy due to friction between the person and the slide, as well as the surrounding air. Consequently, the energy dissipates into the surroundings.

Step 3

(b) Explain which one of the three distances shown in Figure 12 should be used to calculate the work done against the force of friction between the box and the slope.

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Answer

To calculate the work done against the force of friction, we must consider the distance that the box moves along the slope, which must be the actual path taken. In Figure 12, this distance is the length of the slope itself (6.0 m), as the work done against friction is dependent on this distance, rather than the vertical height or horizontal distance.

Step 4

(c) Calculate the kinetic energy of a tennis ball travelling at 28 m/s. The mass of the tennis ball = 58 g. Use the equation: KE = \frac{1}{2} m v^2

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Answer

To calculate the kinetic energy (KE) of the tennis ball, we will use the formula:

KE=12mv2KE = \frac{1}{2} m v^2

First, we need to convert the mass from grams to kilograms:

m=58g=0.058kgm = 58 g = 0.058 kg

Now, substituting in the values:

KE=12(0.058 kg)(28 m/s)2KE = \frac{1}{2} (0.058 \text{ kg}) (28 \text{ m/s})^2

Calculating the kinetic energy:

KE=12×0.058×784KE = \frac{1}{2} \times 0.058 \times 784 KE=22.752 JKE = 22.752 \text{ J}

Thus, the kinetic energy of the tennis ball is approximately 22.75 J.

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