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A child is stationary on a swing - Edexcel - GCSE Physics - Question 5 - 2012 - Paper 1

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A child is stationary on a swing. (a) The child is given a push by his brother to start him swinging. His brother applies a steady force of 84 N over a distance of ... show full transcript

Worked Solution & Example Answer:A child is stationary on a swing - Edexcel - GCSE Physics - Question 5 - 2012 - Paper 1

Step 1

Calculate the work done by this force.

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Answer

To calculate the work done (W), we can use the formula:

W=FimesdW = F imes d

where:

  • W = work done (Joules)
  • F = force applied (Newtons)
  • d = distance over which the force is applied (meters)

Substituting in the values:

W=84imes0.25W = 84 imes 0.25

Calculating:

W=21extJW = 21 ext{ J}

Step 2

State how much energy is transferred by this force.

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Answer

The energy transferred by this force is equal to the work done, which we calculated to be:

21 J

Step 3

Show that the velocity of the child at this point is about 2.3 m/s.

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Answer

To find the velocity (v) of the child, we can use the kinetic energy formula:

KE=12mv2KE = \frac{1}{2} mv^2

where:

  • KE = kinetic energy (Joules)
  • m = mass (kg)
  • v = velocity (m/s)

Rearranging the formula gives:

v=2×KEmv = \sqrt{\frac{2 \times KE}{m}}

Substituting the values:

v=2×7127v = \sqrt{\frac{2 \times 71}{27}}

Calculating:

v=14227≈5.26≈2.29extm/sv = \sqrt{\frac{142}{27}} \approx \sqrt{5.26} \approx 2.29 ext{ m/s}

Therefore, we can conclude that the velocity of the child at this point is approximately 2.3 m/s.

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