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23 (a) Factorise $x^2 + 10x + 24$ - OCR - GCSE Maths - Question 23 - 2023 - Paper 2

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Question 23

23-(a)-Factorise-$x^2-+-10x-+-24$-OCR-GCSE Maths-Question 23-2023-Paper 2.png

23 (a) Factorise $x^2 + 10x + 24$. (b) Write down the solutions to $x^2 + 10x + 24 = 0$.

Worked Solution & Example Answer:23 (a) Factorise $x^2 + 10x + 24$ - OCR - GCSE Maths - Question 23 - 2023 - Paper 2

Step 1

Factorise $x^2 + 10x + 24$

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Answer

To factorise the quadratic expression x2+10x+24x^2 + 10x + 24, we need to find two numbers that multiply to 24 (the constant term) and add up to 10 (the coefficient of the linear term). The numbers 6 and 4 fulfill these conditions since:

  • 6×4=246 \times 4 = 24
  • 6+4=106 + 4 = 10

Thus, we can express the quadratic as: x2+10x+24=(x+6)(x+4)x^2 + 10x + 24 = (x + 6)(x + 4)

Step 2

Write down the solutions to $x^2 + 10x + 24 = 0$

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Answer

To find the solutions of the equation x2+10x+24=0x^2 + 10x + 24 = 0, we can use the factored form we found earlier: (x+6)(x+4)=0(x + 6)(x + 4) = 0 Setting each factor to zero gives us:

  1. x+6=0x=6x + 6 = 0 \Rightarrow x = -6
  2. x+4=0x=4x + 4 = 0 \Rightarrow x = -4

Hence, the solutions are:

  • x=6x = -6 or x=4x = -4.

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