The diagram shows a kite, ABCD - OCR - GCSE Maths - Question 21 - 2019 - Paper 1

Given the ratio of angle DAE : angle EAF = 1 : 4, we can let angle DAE = y and angle EAF = 4y.

In triangle AEF, the sum of the angles must equal 180°:

$y + 4y + 60° = 180°$

This simplifies to:

$5y + 60° = 180°$

Subtracting 60° from both sides gives:

$5y = 120°$

Thus, dividing by 5 yields:

$y = 24°$

So, angle DAE = 24° and angle EAF = 96°. Angle x (which is angle EDF) can be found using the fact that triangle ABC is a kite and therefore angles DAE and EAF are supplementary:

$x = 180° - 96° = 84°$

Therefore, angle x = 84°.