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Reece is given this question - OCR - GCSE Maths - Question 13 - 2021 - Paper 1

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Reece is given this question. Write 20 as a product of prime factors. Give your answer in index form. Reece's answer is $2 \times 2 \times 5$. Is Reece correct? E... show full transcript

Worked Solution & Example Answer:Reece is given this question - OCR - GCSE Maths - Question 13 - 2021 - Paper 1

Step 1

Write 20 as a product of prime factors. Give your answer in index form.

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Answer

To express 20 as a product of prime factors, we can start by dividing by the smallest prime number:

  1. Divide 20 by 2: ( 20 \div 2 = 10 )
  2. Divide 10 by 2: ( 10 \div 2 = 5 )
  3. Since 5 is a prime number, we cannot divide further.

Thus, the prime factorization of 20 is: ( 20 = 2^2 \times 5^1 ).

In index form, the answer is: ( 20 = 2^2 \times 5 ).

Reece's answer 2×2×52 \times 2 \times 5 is correct, but it should be expressed as ( 2^2 \times 5 ).

Step 2

Complete the power of 2.

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Answer

Given the equation (\frac{1}{8} = 2^{_}), we can rewrite 8 as a power of 2: ( 8 = 2^3 ). Therefore, (\frac{1}{8} = 2^{-3}). So, we get:

(\frac{1}{8} = 2^{-3} ). Thus, the blank should be filled with -3.

Step 3

Work out. \(\sqrt{81} \times 2^3\)

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Answer

First, we calculate (\sqrt{81}):
(\sqrt{81} = 9 ).

Now, calculate (2^3):
(2^3 = 8 ).

Now, multiply the two results together: (9 \times 8 = 72).

Therefore, the final answer is (72).

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