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Question 12
A solid metal sphere has mass 235 g. The density of the metal is 7.78 g/cm³. Show that the surface area of this sphere is 46.9 cm², correct to 3 significant figures... show full transcript
Step 1
Answer
To find the radius of the sphere, we first use the mass and the density to calculate the volume.
Using the formula for density:
[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} ]
We rearrange it to find volume:
[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} = \frac{235 \text{ g}}{7.78 \text{ g/cm}^3} \approx 30.17 \text{ cm}^3 ]
Step 2
Answer
Using the volume formula for a sphere:
[ V = \frac{4}{3} \pi r^3 ]
We can solve for radius r:
[ 30.17 = \frac{4}{3} \pi r^3 ]
Rearranging gives:
[ r^3 = \frac{30.17 \times 3}{4\pi} \approx 7.19 ]
Taking the cube root, we find:
[ r \approx 1.95 \text{ cm} ]
Step 3
Answer
Now, using the formula for the surface area of a sphere:
[ A = 4 \pi r^2 ]
We substitute the value of r:
[ A = 4\pi (1.95)^2 \approx 46.9 \text{ cm}^2 ]
This confirms that the surface area is approximately 46.9 cm², correct to 3 significant figures.
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