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AOB is a sector of a circle, centre O and radius 6 cm - OCR - GCSE Maths - Question 12 - 2018 - Paper 5

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AOB is a sector of a circle, centre O and radius 6 cm. The length of arc AB is 5 cm. Find the area of the sector. Give your answer in terms of π.

Worked Solution & Example Answer:AOB is a sector of a circle, centre O and radius 6 cm - OCR - GCSE Maths - Question 12 - 2018 - Paper 5

Step 1

Find the angle at the centre (O)

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Answer

The formula for the length of an arc is given by:

L=θ360×2πrL = \frac{\theta}{360} \times 2 \pi r

Where:

  • L is the length of the arc (5 cm)
  • r is the radius (6 cm)
  • (\theta) is the angle at the centre in degrees.

Substituting the known values:

5=θ360×2π×65 = \frac{\theta}{360} \times 2 \pi \times 6

Rearranging gives: θ=5×3602π×6\theta = \frac{5 \times 360}{2 \pi \times 6}

This simplifies to: θ=5×36012π=150π\theta = \frac{5 \times 360}{12 \pi} = \frac{150}{\pi}

Step 2

Find the area of the sector

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Answer

The area (A) of a sector is given by:

A=θ360×πr2A = \frac{\theta}{360} \times \pi r^2

Substituting (\theta = \frac{150}{\pi}) and r = 6:

A=150360×π×(6)2A = \frac{150}{360} \times \pi \times (6)^2

This simplifies to: A=150360×π×36=150×36π360A = \frac{150}{360} \times \pi \times 36 = \frac{150 \times 36 \pi}{360}

Reducing gives: A=15πA = 15\pi

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