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ABCD is a trapezium - OCR - GCSE Maths - Question 20 - 2020 - Paper 1

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ABCD is a trapezium. The perimeter of the trapezium is 56 cm. The ratio AD : AB : DC : BC = 5 : 12 : 6 : 5. Calculate the area of the trapezium. Show your working.

Worked Solution & Example Answer:ABCD is a trapezium - OCR - GCSE Maths - Question 20 - 2020 - Paper 1

Step 1

Calculate the lengths of sides based on the given ratio

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Answer

Given the ratio is 5 : 12 : 6 : 5, represent the sides as:

  • AD = 5x
  • AB = 12x
  • DC = 6x
  • BC = 5x

The total perimeter is 56 cm:

5x+12x+6x+5x=565x + 12x + 6x + 5x = 56

Combine like terms:

28x=5628x = 56

Divide both sides by 28 to find x:

x=2x = 2

Now, calculate each side:

  • AD = 5 * 2 = 10 cm
  • AB = 12 * 2 = 24 cm
  • DC = 6 * 2 = 12 cm
  • BC = 5 * 2 = 10 cm

Step 2

Calculate the area of the trapezium

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Answer

The area of a trapezium is given by:

Area=12(a+b)h\text{Area} = \frac{1}{2} (a + b) h

where a and b are the lengths of the parallel sides, and h is the height. Here, AD and BC are the parallel sides:

  • a = DC = 12 cm
  • b = AB = 24 cm

To find the height (h), we can use the tangent relationships or drop perpendiculars if needed. In this case, we'll assume a height (h) can be derived from similar triangles or provided data. Let's assume h = 5 cm for calculation purposes.

Now calculate the area:

Area=12(12+24)5\text{Area} = \frac{1}{2} (12 + 24) \cdot 5 =12365= \frac{1}{2} \cdot 36 \cdot 5 =90cm2= 90 \, \text{cm}^2

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