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Kai has four differently numbered cards - OCR - GCSE Maths - Question 2 - 2023 - Paper 1

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Kai has four differently numbered cards. - The range of the numbers is 14. - The median of the numbers is 9. - All the numbers are prime numbers. - The lowest numbe... show full transcript

Worked Solution & Example Answer:Kai has four differently numbered cards - OCR - GCSE Maths - Question 2 - 2023 - Paper 1

Step 1

The range of the numbers is 14.

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Answer

The range is defined as the difference between the highest and lowest numbers. Given the lowest number is 5 and the range is 14, we can calculate the highest number as follows:

extHighestNumber=extLowestNumber+extRange=5+14=19 ext{Highest Number} = ext{Lowest Number} + ext{Range} = 5 + 14 = 19

Step 2

The median of the numbers is 9.

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With four numbers, the median is calculated as the average of the two middle numbers when arranged in order. Let the numbers be represented as a1,a2,a3,a4a_1, a_2, a_3, a_4 where a1<a2<a3<a4a_1 < a_2 < a_3 < a_4. Given the median is 9, we can set up the equation:

rac{a_2 + a_3}{2} = 9 ightarrow a_2 + a_3 = 18

Step 3

All the numbers are prime numbers.

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Prime numbers that can be considered include 5, 7, 11, 13, 17, and 19. Since the lowest number is 5 and the highest is 19, we need to find two other prime numbers that fit this criteria while also giving a median of 9.

Step 4

The lowest number is 5.

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From the previous step, we can choose 7 and 11 as the next two prime numbers. Arranging them gives us 5, 7, 11, and 19. Checking the median:

rac{7 + 11}{2} = 9

This is correct. Thus, the numbers on the cards in order are: 5, 7, 11, 19.

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