Use the formula $F = \frac{s}{\sqrt{tm}}$ to find the value of $F$ when $s = 5.8 \times 10^{6}$ t = $4.1 \times 10^{8}$ $m = 3.7 \times 10^{-2}$ Give your answer in standard form, correct to 2 significant figures. - OCR - GCSE Maths - Question 2 - 2019 - Paper 4

Now, we take the square root of $tm$:

Substituting the values back into the original formula:

$F = \frac{s}{\sqrt{tm}} = \frac{5.8 \times 10^{6}}{3.55 \times 10^{3}}$

Carrying out the division:

$F \approx \frac{5.8}{3.55} \times 10^{6 - 3} \approx 1.63 \times 10^{3}$

Now round to 2 significant figures to get:

$F \approx 1.6 \times 10^{3}$