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Asha worked out $$\frac{326.8 \times (6.94 - 3.4)}{59.4}$$ - OCR - GCSE Maths - Question 3 - 2018 - Paper 1

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Asha-worked-out--$$\frac{326.8-\times-(6.94---3.4)}{59.4}$$-OCR-GCSE Maths-Question 3-2018-Paper 1.png

Asha worked out $$\frac{326.8 \times (6.94 - 3.4)}{59.4}$$. She got an answer of 19.5, correct to 3 significant figures. Write each number correct to 1 significan... show full transcript

Worked Solution & Example Answer:Asha worked out $$\frac{326.8 \times (6.94 - 3.4)}{59.4}$$ - OCR - GCSE Maths - Question 3 - 2018 - Paper 1

Step 1

Write each number correct to 1 significant figure

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Answer

  • For 326.8: The first significant figure is 3, so it becomes 300.

  • For 6.94: The first significant figure is 7, so it becomes 7.

  • For 3.4: The first significant figure is 3, so it becomes 3.

  • For 59.4: The first significant figure is 6, so it becomes 60.

Step 2

Is Asha's answer reasonable?

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Answer

Calculating with these rounded figures:

300×(73)60=300×460=20\frac{300 \times (7 - 3)}{60} = \frac{300 \times 4}{60} = 20.

This estimated answer of 20 is close to Asha's answer of 19.5. Thus, Asha’s answer is reasonable.

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