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A model railway is built using the scale 1 : 87 - OCR - GCSE Maths - Question 13 - 2017 - Paper 1

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A model railway is built using the scale 1 : 87. On the model railway, the distance between the rails is 16.5mm. Calculate, in metres, the distance between the rai... show full transcript

Worked Solution & Example Answer:A model railway is built using the scale 1 : 87 - OCR - GCSE Maths - Question 13 - 2017 - Paper 1

Step 1

Calculate distance between the rails for a full-size train

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Answer

To find the distance between the rails for the full-size train, we first convert the model distance into meters. Given the scale is 1:87, we can use the following formula:

extRealDistance=extModelDistance×extScaleFactor ext{Real Distance} = ext{Model Distance} \times ext{Scale Factor}

Here, the model distance is 16.5 mm, which must be converted to meters:

extModelDistanceinmeters=16.5extmm×1extm1000extmm=0.0165extm ext{Model Distance in meters} = 16.5 ext{ mm} \times \frac{1 ext{ m}}{1000 ext{ mm}} = 0.0165 ext{ m}

Now applying the scale factor:

extRealDistance=0.0165extm×87=1.4355extm ext{Real Distance} = 0.0165 ext{ m} \times 87 = 1.4355 ext{ m}

Thus, the distance between the rails for a full-size train is approximately 1.44 m when rounded to three significant figures.

Step 2

Is Trevor's calculation correct?

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Answer

To determine if Trevor's calculation of 334 cm³ for the model train carriage is correct, we first convert the volume of the full-size train carriage to cm³:

extFullSizeVolumeincm3=220extm3×1003=220,000,000extcm3 ext{Full-Size Volume in cm³} = 220 ext{ m³} \times 100^3 = 220,000,000 ext{ cm³}

Then, using the scale (1:87), we estimate the model volume:

extModelVolume=220,000,000873=220,000,000÷658503=334.2extcm3 ext{Model Volume} = \frac{220,000,000}{87^3} = 220,000,000 \div 658503 = 334.2 ext{ cm³}

Since Trevor calculated the volume as 334 cm³, which rounds to the nearest significant figures correctly, we conclude that Trevor's calculation is indeed correct.

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