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Finley has 72 sweets - OCR - GCSE Maths - Question 15 - 2023 - Paper 1

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Finley has 72 sweets. Finley gives - 25% of the sweets to Alex. - \( \frac{1}{6} \) of the sweets to Umi. Show that Finley has \( \frac{7}{12} \) of the sweets left.

Worked Solution & Example Answer:Finley has 72 sweets - OCR - GCSE Maths - Question 15 - 2023 - Paper 1

Step 1

Calculate the sweets given to Alex

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Answer

To find the amount of sweets given to Alex, calculate 25% of 72:

25% of 72=25100×72=1825\% \text{ of } 72 = \frac{25}{100} \times 72 = 18

So, Finley gives 18 sweets to Alex.

Step 2

Calculate the sweets given to Umi

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Answer

Next, to find the sweets given to Umi, calculate ( \frac{1}{6} ) of 72:

16 of 72=726=12\frac{1}{6} \text{ of } 72 = \frac{72}{6} = 12

Finley gives 12 sweets to Umi.

Step 3

Calculate the total sweets given away

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Answer

Now, add the sweets given to Alex and Umi to find the total given away:

Total given =18+12=30Total \text{ given } = 18 + 12 = 30

Step 4

Calculate the sweets left

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Answer

Finally, subtract the total given away from the initial amount to find how many sweets are left:

Sweets left =7230=42Sweets \text{ left } = 72 - 30 = 42

To show this as a fraction of the total, calculate:

Sweets leftTotal=4272=712\frac{Sweets \text{ left}}{Total} = \frac{42}{72} = \frac{7}{12}

Thus, Finley has ( \frac{7}{12} ) of the sweets left.

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