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Diners choose one starter and one main from the options given in the table below - OCR - GCSE Maths - Question 8 - 2017 - Paper 1

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Diners choose one starter and one main from the options given in the table below. Vegetarian dishes are indicated with a (v). | Starter | Main ... show full transcript

Worked Solution & Example Answer:Diners choose one starter and one main from the options given in the table below - OCR - GCSE Maths - Question 8 - 2017 - Paper 1

Step 1

Work out the fraction of all the meal combinations which have at least one vegetarian option.

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Answer

To determine the fraction of meal combinations with at least one vegetarian option, we first identify the possible starters and mains.

Starters:

  1. Cheese salad (v)
  2. Prawn cocktail
  3. Mozzarella sticks (v)

Mains:

  1. Steak and chips
  2. Fish and chips
  3. Tomato pizza (v)
  4. Pork chops
  5. Nut cutlet (v)

Total combinations:
There are 3 starters and 5 mains, so the total number of combinations is: 3imes5=153 imes 5 = 15

Combinations with at least one vegetarian option:

  • For each starter, we check possible mains:
    • Cheese salad (v): {Steak, Fish, Tomato, Pork, Nut} = 5 combinations
    • Prawn cocktail: {Steak, Fish, Tomato, Pork, Nut} = 5 combinations
    • Mozzarella sticks (v): {Steak, Fish, Tomato, Pork, Nut} = 5 combinations
    • Totals with at least one vegetarian option are:
    1. Cheese salad (v) with any main (5)
    2. Mozzarella sticks (v) with any main (5)
    3. Prawn B with packs of only vegetarian mains - Tomato Pizza (v), Nut Cutlet (v) counting for the mains with 2 vegetarian choices.

Thus, we have: 5+5+2=125 + 5 + 2 = 12 combinations with at least one vegetarian option.

Fraction of combinations with at least one vegetarian option: 1215=45\frac{12}{15} = \frac{4}{5}

Step 2

How many different three-course meal combinations are available?

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Answer

To find the total number of meal combinations, we add the dessert options to the previously calculated meal combinations.

Dessert Options:
There are 6 dessert options available.

Total Combinations:
Since there are 15 possible starter-main combinations and 6 dessert options, the total number of three-course meal combinations is given by: 15×6=9015 \times 6 = 90

Therefore, there are 90 different three-course meal combinations available.

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