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The value of a car, £V, is given by V = 16500 × 0.82ⁿ where n is the number of years after it is bought from new - OCR - GCSE Maths - Question 12 - 2018 - Paper 1

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The value of a car, £V, is given by V = 16500 × 0.82ⁿ where n is the number of years after it is bought from new. (a) Write down the value of the car when new. (... show full transcript

Worked Solution & Example Answer:The value of a car, £V, is given by V = 16500 × 0.82ⁿ where n is the number of years after it is bought from new - OCR - GCSE Maths - Question 12 - 2018 - Paper 1

Step 1

Write down the value of the car when new.

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Answer

To find the value of the car when new, we refer to the formula provided:

V=16500×0.820V = 16500 × 0.82^0

Since when the car is new, n = 0, therefore:

V=16500×1=16500V = 16500 × 1 = 16500

Thus, the value of the car when new is £16500.

Step 2

Write down the annual percentage decrease in the value of the car.

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Answer

The formula for the value of the car is:

V=16500×0.82nV = 16500 × 0.82^n

The value of the car decreases by a factor of 0.82 each year. To find the annual percentage decrease, we calculate:

extPercentagedecrease=(10.82)×100=0.18×100=18% ext{Percentage decrease} = (1 - 0.82) × 100 = 0.18 × 100 = 18\%

Thus, the annual percentage decrease in the value of the car is 18%.

Step 3

Show that the value of the car after 4 years is less than half its value when new.

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Answer

Firstly, we calculate the value of the car after 4 years using the formula:

V=16500×0.824V = 16500 × 0.82^4

Calculating this:

0.8240.45240.82^4 ≈ 0.4524

Now substitute this back into the equation:

V16500×0.45247465.95V ≈ 16500 × 0.4524 ≈ 7465.95

Next, we find half the value when new:

Half of £16500=8250\text{Half of £16500} = 8250

Now we compare:

Since 7465.95 < 8250, we can conclude that the value of the car after 4 years is indeed less than half its value when new.

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