1. Work out - OCR - GCSE Maths - Question 1 - 2018 - Paper 5
Question 1
1. Work out.
(a) \( \sqrt{64} \times 2^{-1} \)
(b) \( 4.3 \times 10^{5} + 3.8 \times 10^{4} \)
Give your answer in standard form.
Worked Solution & Example Answer:1. Work out - OCR - GCSE Maths - Question 1 - 2018 - Paper 5
(a) \( \sqrt{64} \times 2^{-1} \)
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To solve ( \sqrt{64} \times 2^{-1} ), we first compute ( \sqrt{64} = 8 ). Then we find ( 2^{-1} = \frac{1}{2} ).
Now, we multiply:
[
8 \times \frac{1}{2} = 4
]
Thus, the final answer for part (a) is ( 4 ).
(b) \( 4.3 \times 10^{5} + 3.8 \times 10^{4} \)
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To add ( 4.3 \times 10^{5} ) and ( 3.8 \times 10^{4} ), we express both terms in the same power of ten.
We convert ( 3.8 \times 10^{4} ) to the same power as ( 10^{5} ):
[
3.8 \times 10^{4} = 0.38 \times 10^{5}
]
Now we perform the addition:
[
4.3 \times 10^{5} + 0.38 \times 10^{5} = (4.3 + 0.38) \times 10^{5} = 4.68 \times 10^{5}
]
Therefore, the final answer for part (b) is ( 4.68 \times 10^{5} ) in standard form.
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