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Write down the value of \( \sqrt{27} \) - OCR - GCSE Maths - Question 7 - 2018 - Paper 2

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Write down the value of \( \sqrt{27} \). Work out \( 7^2 \). Write \( 6^{-1} \) as a fraction.

Worked Solution & Example Answer:Write down the value of \( \sqrt{27} \) - OCR - GCSE Maths - Question 7 - 2018 - Paper 2

Step 1

Write down the value of \( \sqrt{27} \)

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Answer

To find the value of ( \sqrt{27} ), we can simplify it as follows:

[ \sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \times \sqrt{3} = 3\sqrt{3} ]
Thus, the value is approximately 5.196 if a decimal is needed.

Step 2

Work out \( 7^2 \)

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Answer

To calculate ( 7^2 ), we multiply 7 by itself:

[ 7^2 = 7 \times 7 = 49 ]
Therefore, the answer is 49.

Step 3

Write \( 6^{-1} \) as a fraction.

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Answer

The expression ( 6^{-1} ) represents the reciprocal of 6. This can be expressed as:

[ 6^{-1} = \frac{1}{6} ]
Hence, the fraction is ( \frac{1}{6} ).

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