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20 (a) Prove that (2x + 1)(3x + 2) + -(3x + 5) + 2 is a perfect square - OCR - GCSE Maths - Question 20 - 2018 - Paper 5

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20 (a) Prove that (2x + 1)(3x + 2) + -(3x + 5) + 2 is a perfect square. (b) Gemma says The equation (2x + 1)(3x + 2) - x(3x + 5) + 2 = -12 has no solutions. Explai... show full transcript

Worked Solution & Example Answer:20 (a) Prove that (2x + 1)(3x + 2) + -(3x + 5) + 2 is a perfect square - OCR - GCSE Maths - Question 20 - 2018 - Paper 5

Step 1

(a) Prove that (2x + 1)(3x + 2) + -(3x + 5) + 2 is a perfect square.

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Answer

To prove that

(2x+1)(3x+2)(3x+5)+2(2x + 1)(3x + 2) - (3x + 5) + 2

is a perfect square, we first need to expand the expression.

  1. Expand the Terms:

    (2x+1)(3x+2)=6x2+4x+3x+2=6x2+7x+2(2x + 1)(3x + 2) = 6x^2 + 4x + 3x + 2 = 6x^2 + 7x + 2

    Now substitute this result back into the initial equation, giving us:

    6x2+7x+2(3x+5)+2 6x^2 + 7x + 2 - (3x + 5) + 2

    Simplifying further, we have:

    6x2+7x+23x5+2=6x2+4x1 6x^2 + 7x + 2 - 3x - 5 + 2 = 6x^2 + 4x - 1

  2. Rearranging the Expression:

    We rewrite it as:

    6x2+4x1=(3x+2)2 6x^2 + 4x - 1 = (3x + 2)^2

    which is a perfect square.

Thus, we have shown that the expression is indeed a perfect square.

Step 2

(b) Explain Gemma's reasoning.

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Answer

Gemma's reasoning is based on the properties of quadratic equations. She states that the equation:

(2x+1)(3x+2)x(3x+5)+2=12(2x + 1)(3x + 2) - x(3x + 5) + 2 = -12

has no solutions. This is due to the fact that when rearranging the equation, if we set it equal to zero, we will end up with a negative discriminant, which indicates that there are no real solutions for the variable x. Specifically, if we manipulate the equation and isolate it to standard form, we might find a situation like:

ax2+bx+c=0extwhereb24ac<0ax^2 + bx + c = 0 ext{ where } b^2 - 4ac < 0

Thus, if the discriminant is less than zero, as Gemma suggests, then the quadratic equation has no real solutions.

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