19
(a) Write $x^2 - 10x + 22$ in the form $(x - a)^2 - b$ - OCR - GCSE Maths - Question 19 - 2020 - Paper 1
Question 19
19
(a) Write $x^2 - 10x + 22$ in the form $(x - a)^2 - b$.
(b) Sketch the graph of $y = x^2 - 10x + 22$.
Show clearly the coordinates of any turning points and the... show full transcript
Worked Solution & Example Answer:19
(a) Write $x^2 - 10x + 22$ in the form $(x - a)^2 - b$ - OCR - GCSE Maths - Question 19 - 2020 - Paper 1
Step 1
Write $x^2 - 10x + 22$ in the form $(x - a)^2 - b$
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Answer
To rewrite the quadratic expression x2−10x+22 in the form (x−a)2−b, we will complete the square.
Start with the expression:
x2−10x+22
Take the coefficient of x, which is −10, halve it to get −5, and then square it to get 25. We will now add and subtract this value:
x2−10x+25−25+22
This can be rearranged as:
(x−5)2−3
Thus, we have:
(x−5)2−3
Step 2
Sketch the graph of $y = x^2 - 10x + 22$
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Answer
To sketch the graph of y=x2−10x+22, we will first identify key features such as turning points and the y-intercept.
Vertex/Turning Point: From our completed square form (x−5)2−3, we can see that the turning point (vertex) is at (5,−3). This is where the minimum value of the function occurs.
Y-Intercept: To find the y-intercept, we set x=0:
y=02−10(0)+22=22
Thus, the y-intercept is at (0,22).
Graph Characteristics: The graph is a parabola opening upwards since the coefficient of x2 is positive. It will cross the y-axis at (0,22) and have its minimum point at (5,−3).
Sketch: Draw a standard Cartesian plane and plot the points (5,−3) and (0,22). Then, sketch the parabola, ensuring that it opens upwards and passes through the y-intercept.