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22 In this question, all measurements are in centimetres - OCR - GCSE Maths - Question 22 - 2021 - Paper 3

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22 In this question, all measurements are in centimetres. The square and the rectangle have the same area. (a) Show that $x^2 - 8x - 20 = 0$. (b) Solve $x^2 - 8x... show full transcript

Worked Solution & Example Answer:22 In this question, all measurements are in centimetres - OCR - GCSE Maths - Question 22 - 2021 - Paper 3

Step 1

Show that $x^2 - 8x - 20 = 0$

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Answer

To show that the square and rectangle have the same area:

  1. Calculate the area of the square:

    • The side length of the square is xx, so the area is: extAreaextsquare=x2 ext{Area}_{ ext{square}} = x^2
  2. Calculate the area of the rectangle:

    • The width is 4 cm and the length is given by 2x+52x + 5. Therefore, the area is: extAreaextrectangle=4(2x+5)=8x+20 ext{Area}_{ ext{rectangle}} = 4(2x + 5) = 8x + 20
  3. Set the areas equal: x2=8x+20x^2 = 8x + 20

  4. Rearrange the equation:

    • Move all terms to one side: x28x20=0x^2 - 8x - 20 = 0
    • This shows the required equation.

Step 2

Solve $x^2 - 8x - 20 = 0$

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Answer

To solve the equation x28x20=0x^2 - 8x - 20 = 0, we can factor it:

  1. Identify factors:

    • We need two numbers that multiply to -20 and add to -8. These numbers are -10 and +2.
  2. Factor the equation: (x10)(x+2)=0(x - 10)(x + 2) = 0

  3. Find the solutions:

    • Set each factor to zero:
      • x10=0x - 10 = 0 or x+2=0x + 2 = 0
    • This gives:
      • x=10x = 10 or x=2x = -2
  4. Write the final answer:

    • Therefore, the solutions are: x=10x = 10 or x=2x = -2

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