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The value of a car, £V, is given by V = 16500 × 0.82ⁿ where n is the number of years after it is bought from new - OCR - GCSE Maths - Question 12 - 2018 - Paper 1

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The value of a car, £V, is given by V = 16500 × 0.82ⁿ where n is the number of years after it is bought from new. (a) Write down the value of the car when new. (... show full transcript

Worked Solution & Example Answer:The value of a car, £V, is given by V = 16500 × 0.82ⁿ where n is the number of years after it is bought from new - OCR - GCSE Maths - Question 12 - 2018 - Paper 1

Step 1

Write down the value of the car when new.

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Answer

The value of the car when new is given by replacing n with 0 in the formula:

V=16500×0.820=16500×1=16500V = 16500 × 0.82^0 = 16500 × 1 = 16500

Thus, the value of the car when new is £16,500.

Step 2

Write down the annual percentage decrease in the value of the car.

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Answer

To find the annual percentage decrease, we look at the factor by which the value decreases each year. From the formula, each year the value of the car is multiplied by 0.82.

The annual percentage decrease is given by:

extPercentageDecrease=(10.82)×100=0.18×100=18% ext{Percentage Decrease} = (1 - 0.82) × 100 = 0.18 × 100 = 18\%

Thus, the annual percentage decrease in the value of the car is 18%.

Step 3

Show that the value of the car after 4 years is less than half its value when new.

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Answer

First, we calculate the value of the car after 4 years by substituting n = 4 into the formula:

V=16500×0.824V = 16500 × 0.82^4

Calculating this gives:

V=16500×0.45067439.85V = 16500 × 0.4506 ≈ 7439.85

Now, half of the initial value when new is:

165002=8250\frac{16500}{2} = 8250

We see that:

7439.85<82507439.85 < 8250

Thus, the value of the car after 4 years is indeed less than half its value when new.

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