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19 (a) Fountain A squirts water every 24 minutes - OCR - GCSE Maths - Question 19 - 2021 - Paper 1

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19 (a) Fountain A squirts water every 24 minutes. Fountain B squirts water every 42 minutes. They squirt water together at 15:19. Find the next time they squirt wat... show full transcript

Worked Solution & Example Answer:19 (a) Fountain A squirts water every 24 minutes - OCR - GCSE Maths - Question 19 - 2021 - Paper 1

Step 1

Find the next time they squirt water together.

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Answer

To find the next time that fountain A and fountain B squirt water together, we first need to determine the least common multiple (LCM) of their squirt intervals, which are 24 minutes and 42 minutes.

  1. Calculate LCM:

    The prime factorization of 24 is: 24=23×3124 = 2^3 \times 3^1

    The prime factorization of 42 is: 42=21×31×7142 = 2^1 \times 3^1 \times 7^1

    The LCM is found by taking the highest power of each prime: LCM=23×31×71=168LCM = 2^3 \times 3^1 \times 7^1 = 168

Thus, they will squirt together again after 168 minutes.

  1. Convert minutes into hours and minutes:
    • 168 minutes is 2 hours and 48 minutes.

    • Starting from 15:19, add 2 hours 48 minutes:

    • 15:19 + 2:48 = 18:07

    Therefore, the next time they squirt water together is at 18:07.

Step 2

Find the size of each group and the total number of groups.

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Answer

To find the size of each group and the total number of groups, we need to determine the greatest common divisor (GCD) of the number of students from Year 8 and Year 9, which are 60 and 105 respectively.

  1. Calculate GCD:

    The prime factorization of 60 is: 60=22×31×5160 = 2^2 \times 3^1 \times 5^1

    The prime factorization of 105 is: 105=31×51×71105 = 3^1 \times 5^1 \times 7^1

    The GCD can be taken by the lowest powers of the common primes: GCD=31×51=15GCD = 3^1 \times 5^1 = 15

Thus, each group should have 15 students.

  1. Calculate the total number of groups:

    • From Year 8: 6015=4\frac{60}{15} = 4 groups
    • From Year 9: 10515=7\frac{105}{15} = 7 groups

    Therefore, the total number of groups is: 4+7=114 + 7 = 11 groups.

In summary:

  • Size of each group = 15
  • Total number of groups = 11

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