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Kai has four differently numbered cards - OCR - GCSE Maths - Question 2 - 2023 - Paper 1

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Kai has four differently numbered cards. - The range of the numbers is 14. - The median of the numbers is 9. - All the numbers are prime numbers. - The lowest numbe... show full transcript

Worked Solution & Example Answer:Kai has four differently numbered cards - OCR - GCSE Maths - Question 2 - 2023 - Paper 1

Step 1

The range of the numbers is 14.

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Answer

The range is calculated by subtracting the lowest number from the highest number. Given that the lowest number is 5, we can find the highest number:

extHighestnumber=extLowestnumber+extRange=5+14=19 ext{Highest number} = ext{Lowest number} + ext{Range} = 5 + 14 = 19

Thus, the highest number is 19.

Step 2

The median of the numbers is 9.

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For four numbers, the median is the average of the two middle numbers when organized in ascending order. Let the numbers be represented as a1,a2,a3,a4a_1, a_2, a_3, a_4 where a1<a2<a3<a4a_1 < a_2 < a_3 < a_4. The median is given by:

ext{Median} = rac{a_2 + a_3}{2} = 9

This implies that a2+a3=18a_2 + a_3 = 18. As they are both prime numbers, we need to consider prime numbers close to 9.

Step 3

All the numbers are prime numbers.

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The prime numbers between 5 and 19 are: 5, 7, 11, 13, 17, 19. We need to choose four prime numbers including 5 and 19, while also ensuring that their median is 9.

Considering combinations: (5, 7, 11, 19) gives a median of 7+112=9\frac{7 + 11}{2} = 9, which suits our condition.

Step 4

The lowest number is 5.

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We have already established that the lowest number is 5, and the combination of chosen numbers is (5, 7, 11, 19). Therefore, the numbers on the cards in order of size are: 5, 7, 11, 19.

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