17 (a) Write $x^2 + 8x + 3$ in the form $(x + a)^2 - b$ - OCR - GCSE Maths - Question 18 - 2019 - Paper 5
Question 18
17 (a) Write $x^2 + 8x + 3$ in the form $(x + a)^2 - b$.
(b) Sketch the graph of $y = x^2 + 8x + 3$.
Show clearly the coordinates of any turning points and the y-in... show full transcript
Worked Solution & Example Answer:17 (a) Write $x^2 + 8x + 3$ in the form $(x + a)^2 - b$ - OCR - GCSE Maths - Question 18 - 2019 - Paper 5
Step 1
Write $x^2 + 8x + 3$ in the form $(x + a)^2 - b$.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To rewrite the quadratic expression in the required form, we can complete the square. Start with the expression:
x2+8x+3
Take the coefficient of x, which is 8, divide it by 2, and square it:
(28)2=16
Now rewrite the expression as:
x2+8x+16−16+3
This simplifies to:
(x+4)2−13
Thus, we have:
(x+4)2−13
Step 2
Sketch the graph of $y = x^2 + 8x + 3$. Show clearly the coordinates of any turning points and the y-intercept.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To sketch the graph of the quadratic function y=x2+8x+3, we can identify its vertex and y-intercept.
Turning Point (Vertex): We have already rewritten the function as:
y=(x+4)2−13
The vertex is at the point (−4,−13).
Y-Intercept: To find the y-intercept, we set x=0:
y=02+8(0)+3=3
Therefore, the y-intercept is at (0,3).
Graphing: Plot the vertex at (−4,−13) and the y-intercept at (0,3). Since the parabola opens upwards (the coefficient of x2 is positive), sketch the curve accordingly, ensuring the points are labeled. The graph should reflect the shape of a parabola opening upwards, with the turning point as the minimum point.