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The diagram shows triangle OAB and points C and D - OCR - GCSE Maths - Question 16 - 2019 - Paper 4

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Question 16

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The diagram shows triangle OAB and points C and D. OA = 3a and OB = 3b. C lies on AB such that AC = 2CB. D is such that BD = 2a + b. Show, using vectors, that OCD ... show full transcript

Worked Solution & Example Answer:The diagram shows triangle OAB and points C and D - OCR - GCSE Maths - Question 16 - 2019 - Paper 4

Step 1

AC = 2CB

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Answer

Let the position vector of point C be represented as vector OC. Then, we can express AC in terms of the position vectors:

  1. From the triangle, we have:

    • Vector AC = Vector C - Vector A
    • Vector C = Vector OC = OA + CB
  2. Given that AC = 2CB, we can set up the equation: extVectorAC=2imesextVectorCB ext{Vector AC} = 2 imes ext{Vector CB}

  3. We can express Vector CB as:

    • Vector CB = Vector B - Vector C = OB - OC, where OB = 3b.
  4. Thus, we have: AC=OCOA=CAAC = OC - OA = C - A and substituting in: OCOA=2(3bOC)OC - OA = 2(3b - OC)

Step 2

BD = 2a + b

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Answer

  1. The position vector for point D can be expressed as: extVectorD=extVectorB+(2a+b) ext{Vector D} = ext{Vector B} + (2a + b)

  2. Since BD is defined as the difference in position vectors, we can write: extVectorBD=extVectorDextVectorB=(2a+b) ext{Vector BD} = ext{Vector D} - ext{Vector B} = (2a + b)

  3. Now, we need to show that points O, C, and D are collinear. For this, we can express vectors OC and OD in terms of scalars: extVectorODextVectorOC=k(extVectorOBextVectorOA) ext{Vector OD} - ext{Vector OC} = k( ext{Vector OB} - ext{Vector OA}) for some scalar k.

  4. Thus, by showing that the ratios of the components between OC and OD are equal, we can conclude that OCD forms a straight line.

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