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Alvin has a crate in the shape of a cuboid - OCR - GCSE Maths - Question 18 - 2017 - Paper 1

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Alvin has a crate in the shape of a cuboid. The crate is open at the top. The internal dimensions of the crate are 46 cm long by 46 cm wide by 55 cm high. Alvin has... show full transcript

Worked Solution & Example Answer:Alvin has a crate in the shape of a cuboid - OCR - GCSE Maths - Question 18 - 2017 - Paper 1

Step 1

Calculate the length of the stick that extends out of the crate.

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Answer

To find the length of the stick that extends above the crate, we first determine the height of the crate, which is 55 cm. Since the stick is 95 cm long, we can use the following calculation:

Length extending out = Length of stick - Height of crate

This can be expressed mathematically as:

L=95extcm55extcm=40extcmL = 95 ext{ cm} - 55 ext{ cm} = 40 ext{ cm}

Thus, the length of the stick that extends out of the crate is 40 cm.

Step 2

Calculate the angle the stick makes with the base of the crate.

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Answer

To find the angle, we can use the height of the crate and the length of the stick. The relationship involves the tangent function:

an(heta)=oppositeadjacent an( heta) = \frac{\text{opposite}}{\text{adjacent}}

Here, the opposite side is the height of the crate (55 cm) and the adjacent side is the length that remains in the crate, which we can calculate as:

Length in crate = Length of stick - Length extending out = 95 ext{ cm} - 40 ext{ cm} = 55 ext{ cm}

Then we can write:

an(heta)=55extcm(40extcm)2+(55extcm)2 an( heta) = \frac{55 ext{ cm}}{\sqrt{(40 ext{ cm})^2 + (55 ext{ cm})^2}}

Using the Pythagorean theorem, the length of the stick in the horizontal direction can be found. After calculations, we can use the inverse tangent function to find the angle:

heta=tan1(5540)40.2 heta = \tan^{-1}\left(\frac{55}{40}\right)\approx 40.2^{\circ}

Thus, the angle the stick makes with the base of the crate is approximately 40.2 degrees.

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