ABC is a right-angled triangle - OCR - GCSE Maths - Question 5 - 2019 - Paper 6

To find angle BAC, we can use the sine function, which relates the opposite side and the hypotenuse:

$\sin(BAC) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{AB}{BC}$

Substituting the values:

$\sin(BAC) = \frac{20}{37}$

Now, to find angle BAC, we take the inverse sine:

$BAC = \arcsin\left(\frac{20}{37}\right)$

Using a calculator:

$BAC \approx 34.89^\circ$

Finally, rounding this to one decimal place gives:

$BAC \approx 34.9^\circ$