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Question 23
The diagram shows a regular hexagon made from six equilateral triangles. Each side is 10 cm. The angle ACB is a right angle. (a) Show that AC = 8.66cm, correct to 3... show full transcript
Step 1
Answer
To find the length AC in the right triangle ACB:
Given that both AB and BC are sides of the equilateral triangle, thus:
Since angle ACB is a right angle, we can apply the Pythagorean theorem:%0A %0A %0A %0A %0A %0A We must find AC, however, since it’s the segment connecting the perpendicular heights from A and B to C, we must also note that AC is equal to the vertical height of triangle ABC.
AC can be calculated as the vertical drop from A to C, which forms the base of two right-angled triangles cut across the hexagon's symmetry. The vertical line segment will equal: AC = rac{10 imes ext{sqrt}(3)}{2} \= 8.66 cm
Thus, rounded to three significant figures, AC = 8.66 cm.
Step 2
Answer
To find the area of triangle ACB:
The area of a triangle can be calculated using the formula: ext{Area} = rac{1}{2} imes ext{base} imes ext{height} Here, taking AB as the base and AC as the height:
Therefore: ext{Area} = rac{1}{2} imes 10 imes 8.66
Rounding to three significant figures gives an area of: .
Step 3
Answer
To find the area of the regular hexagon:
The area of a regular hexagon can be calculated using the formula: ext{Area} = rac{3 ext{sqrt}(3)}{2} imes s^2 where s is the length of each side.
Given that each side s = 10 cm: ext{Area} = rac{3 ext{sqrt}(3)}{2} imes 10^2 ext{Area} = rac{3 ext{sqrt}(3)}{2} imes 100 This approximately equals 259.81 cm².
Rounded to appropriate accuracy, the area of the hexagon is: .
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