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The diagram shows two right-angled triangles ABD and BCD, sharing a common side BD - OCR - GCSE Maths - Question 11 - 2018 - Paper 1

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Question 11

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The diagram shows two right-angled triangles ABD and BCD, sharing a common side BD. AD = 10 cm, BC = 12 cm and angle DBC = 60°. Work out the length of AB.

Worked Solution & Example Answer:The diagram shows two right-angled triangles ABD and BCD, sharing a common side BD - OCR - GCSE Maths - Question 11 - 2018 - Paper 1

Step 1

Determine the length of BD

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Answer

In triangle BCD, we can use the cosine formula to find BD.

Using the cosine of angle DBC: BC=BD/cos(60)BC = BD / \cos(60^\circ)

Substituting the known values: 12=BD/0.512 = BD / 0.5

Therefore, solving for BD gives: BD=120.5=6 cmBD = 12 * 0.5 = 6 \text{ cm}

Step 2

Determine the length of AB

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Answer

Now, knowing that AD = 10 cm and BD = 6 cm, we can find the length of AB using the Pythagorean theorem in triangle ABD:

Using: AD2=AB2+BD2AD^2 = AB^2 + BD^2

Substituting the known values: 102=AB2+6210^2 = AB^2 + 6^2 100=AB2+36100 = AB^2 + 36

Rearranging gives: AB2=10036AB^2 = 100 - 36 AB2=64AB^2 = 64

Taking the square root: AB=64=8 cmAB = \sqrt{64} = 8 \text{ cm}

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