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Complete the table for $y = x^2 - 4x + 1$ - OCR - GCSE Maths - Question 7 - 2019 - Paper 1

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Complete the table for $y = x^2 - 4x + 1$. | x | -1 | 0 | 1 | 2 | 3 | 4 | 5 | |-----|----|----|----|----|----|----|----| | y | 6 | 1 | -2 | 1 | 6 | 13... show full transcript

Worked Solution & Example Answer:Complete the table for $y = x^2 - 4x + 1$ - OCR - GCSE Maths - Question 7 - 2019 - Paper 1

Step 1

Complete the table for $y = x^2 - 4x + 1$

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Answer

To complete the table, we need to calculate the values of yy for each corresponding value of xx given in the table. We apply the formula:

  1. For x=1x = -1: y=(1)24(1)+1=1+4+1=6y = (-1)^2 - 4(-1) + 1 = 1 + 4 + 1 = 6

  2. For x=0x = 0: y=(0)24(0)+1=00+1=1y = (0)^2 - 4(0) + 1 = 0 - 0 + 1 = 1

  3. For x=1x = 1: y=(1)24(1)+1=14+1=2y = (1)^2 - 4(1) + 1 = 1 - 4 + 1 = -2

  4. For x=2x = 2: y=(2)24(2)+1=48+1=3y = (2)^2 - 4(2) + 1 = 4 - 8 + 1 = -3

  5. For x=3x = 3: y=(3)24(3)+1=912+1=2y = (3)^2 - 4(3) + 1 = 9 - 12 + 1 = -2

  6. For x=4x = 4: y=(4)24(4)+1=1616+1=1y = (4)^2 - 4(4) + 1 = 16 - 16 + 1 = 1

  7. For x=5x = 5: y=(5)24(5)+1=2520+1=6y = (5)^2 - 4(5) + 1 = 25 - 20 + 1 = 6

Thus, the complete table is:

x-1012345
y61-2-3-216

Step 2

Draw the graph of $y = x^2 - 4x + 1$ for $-1 \leq x \leq 5$

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Answer

To graph the quadratic function y=x24x+1y = x^2 - 4x + 1 from x=1x = -1 to x=5x = 5, we will plot the points calculated from the completed table. The points to plot are:

  • (1,6)(-1, 6)
  • (0,1)(0, 1)
  • (1,2)(1, -2)
  • (2,3)(2, -3)
  • (3,2)(3, -2)
  • (4,1)(4, 1)
  • (5,6)(5, 6)

After plotting these points on the graph, draw a smooth curve through them. Ensure that the curve correctly represents the shape of a parabola, opening upwards.

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