Photo AI

Eve, Jack and Ling share some money in the ratio 2 : 3 : 4 - OCR - GCSE Maths - Question 23 - 2023 - Paper 1

Question icon

Question 23

Eve,-Jack-and-Ling-share-some-money-in-the-ratio-2-:-3-:-4-OCR-GCSE Maths-Question 23-2023-Paper 1.png

Eve, Jack and Ling share some money in the ratio 2 : 3 : 4. Jack gets £720. Work out how much Ling gets. (b) Amir, Beth and Casey share some money in the ratio 3 :... show full transcript

Worked Solution & Example Answer:Eve, Jack and Ling share some money in the ratio 2 : 3 : 4 - OCR - GCSE Maths - Question 23 - 2023 - Paper 1

Step 1

Work out how much Ling gets.

96%

114 rated

Answer

To find how much Ling gets, we first need to determine the total parts in the ratio. The ratio for Eve, Jack, and Ling is:

  • Eve: 2 parts
  • Jack: 3 parts
  • Ling: 4 parts

Total parts = 2 + 3 + 4 = 9 parts.

Since Jack gets £720, we know that 3 parts equal £720. Therefore, the value of each part is:

[ \text{Value of each part} = \frac{720}{3} = 240 ]

Now, we can find out how much Ling gets, which is 4 parts:

[ \text{Ling's share} = 4 \times 240 = 960 ]

Thus, Ling gets £960.

Step 2

Find the value of c.

99%

104 rated

Answer

Let the total amount of money be represented as T. According to the problem, the shares of Amir, Beth, and Casey are in the ratio 3:5:c.

The total parts in the ratio is:

3 (Amir) + 5 (Beth) + c (Casey) = 8 + c.

Since Casey's share is ( \frac{2}{3} ) of the total, we can express Casey's share in terms of T:

[ \text{Casey's share} = \frac{2}{3}T ]

From the ratio, Casey’s share can also be represented as:

[ \text{Casey's share} = \frac{c}{8+c}T ]

Setting these two equations equal to each other gives:

[ \frac{c}{8+c}T = \frac{2}{3}T ]

By cancelling T from both sides, we have:

[ \frac{c}{8+c} = \frac{2}{3} ]

Cross-multiplying gives:

[ 3c = 2(8+c) ]

Expanding this equation:

[ 3c = 16 + 2c ]

Now, isolating c:

[ 3c - 2c = 16
] [ c = 16 ]

Thus, the value of c is 16.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;