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A box contains 200 matches, correct to the nearest ten matches - OCR - GCSE Maths - Question 12 - 2023 - Paper 6

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A box contains 200 matches, correct to the nearest ten matches. (a) Complete the error interval for n, the number of matches in the box. (b) The box is a cuboid wi... show full transcript

Worked Solution & Example Answer:A box contains 200 matches, correct to the nearest ten matches - OCR - GCSE Maths - Question 12 - 2023 - Paper 6

Step 1

(a) Complete the error interval for n, the number of matches in the box.

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Answer

To find the error interval, we need to understand that the value of 200 matches is correct to the nearest ten. This means that the actual number of matches could be 5 less or 5 more than 200. Therefore, the interval is:

195leqnleq205195 \\leq n \\leq 205

Step 2

(b) Show that the smallest possible height of the box is 6 cm.

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Answer

Given:

  • Length (L) = 7 cm, correct to the nearest cm, implies: 6.5L<7.56.5 \leq L < 7.5
  • Width (W) = 5 cm, correct to the nearest cm, implies: 4.5W<5.54.5 \leq W < 5.5
  • Volume (V) = 248 cm³, correct to the nearest cm³, implies: 247.5V<248.5247.5 \leq V < 248.5

We know that: V=L×W×HV = L \times W \times H Hence, H=VL×WH = \frac{V}{L \times W}

To find the minimum height, we would seek to minimize HH:

  1. Calculate the maximum possible values for L and W:
    • Maximum L = 7.5 cm
    • Minimum W = 4.5 cm
  2. Substitute these in the expression of height: H=247.57.5×4.5H = \frac{247.5}{7.5 \times 4.5}

Calculating HH: H=247.533.757.33cmH = \frac{247.5}{33.75} \approx 7.33 \, \text{cm}

Now, check the minimum possible case: 3. Calculate the minimum possible values for L and W:

  • Minimum L = 6.5 cm
  • Maximum W = 5.5 cm
  1. Again substitute in the height expression: H=247.56.5×5.5H = \frac{247.5}{6.5 \times 5.5}

Calculating HH: H=247.535.756.92cmH = \frac{247.5}{35.75} \approx 6.92 \, \text{cm}

Thus, the smallest possible height satisfying all the conditions is indeed: H6cmH \geq 6 \, \text{cm}

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