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Use the formula $s = ut + \frac{1}{2}at^2$ - OCR - GCSE Maths - Question 1 - 2017 - Paper 1

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Question 1

Use-the-formula-$s-=-ut-+-\frac{1}{2}at^2$-OCR-GCSE Maths-Question 1-2017-Paper 1.png

Use the formula $s = ut + \frac{1}{2}at^2$. (a) Calculate $s$ when $u = 5$, $t = 10$ and $a = 3$. (b) Make $a$ the subject of the formula.

Worked Solution & Example Answer:Use the formula $s = ut + \frac{1}{2}at^2$ - OCR - GCSE Maths - Question 1 - 2017 - Paper 1

Step 1

(a) Calculate $s$ when $u = 5$, $t = 10$ and $a = 3$.

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Answer

To calculate the distance ss, we can substitute the given values into the equation:

s=ut+12at2s = ut + \frac{1}{2}at^2

Substituting the values: s=(5)(10)+12(3)(102)s = (5)(10) + \frac{1}{2}(3)(10^2)

Calculating the first term: s=50+12(3)(100)s = 50 + \frac{1}{2}(3)(100)

Calculating the second term: s=50+3002s = 50 + \frac{300}{2}

s=50+150s = 50 + 150

Thus, the final value is: s=200s = 200

Step 2

(b) Make $a$ the subject of the formula.

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Answer

Starting with the formula: s=ut+12at2s = ut + \frac{1}{2}at^2

To make aa the subject, we will isolate aa on one side. First, subtract utut from both sides:

sut=12at2s - ut = \frac{1}{2}at^2

Next, multiply both sides by 22:

2(sut)=at22(s - ut) = at^2

Finally, divide both sides by t2t^2:

a=2(sut)t2a = \frac{2(s - ut)}{t^2}

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