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Here are the first four terms of a sequence - OCR - GCSE Maths - Question 14 - 2021 - Paper 1

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Here are the first four terms of a sequence. 8 15 22 29 (i) Write down the next term in the sequence. (ii) Explain how you worked out your answer. (b) The nth... show full transcript

Worked Solution & Example Answer:Here are the first four terms of a sequence - OCR - GCSE Maths - Question 14 - 2021 - Paper 1

Step 1

(a)(i) Write down the next term in the sequence.

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Answer

To find the next term in the sequence, we first identify the pattern in the given terms: 8, 15, 22, 29.

Calculating the differences between consecutive terms gives:

  • From 8 to 15: 158=715 - 8 = 7
  • From 15 to 22: 2215=722 - 15 = 7
  • From 22 to 29: 2922=729 - 22 = 7

Since the difference is consistent at 7, we can determine the next term by adding 7 to the last term:

29+7=3629 + 7 = 36

Thus, the next term is 36.

Step 2

(a)(ii) Explain how you worked out your answer.

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Answer

I worked out my answer by first calculating the differences between the consecutive terms of the sequence. Each difference was found to be 7, indicating a linear pattern consistent throughout the sequence. By adding this common difference of 7 to the last term (29), I deduced that the next term must be 36.

Step 3

(b) Explain why 32 is not a term in this sequence.

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Answer

In the sequence defined by the formula 4n+24n + 2, we can determine the terms by substituting integer values for nn. Let's check what values of nn correspond to the term 32:

Setting the equation 4n+2=324n + 2 = 32 leads to: 4n=3224n = 32 - 2 4n=304n = 30 n=7.5n = 7.5

Since nn must be a whole number (as it represents the position in the sequence), 32 cannot be obtained from this formula, and thus, it is not a term in the sequence.

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