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The area of the triangle is equal to the area of the trapezium - OCR - GCSE Maths - Question 15 - 2020 - Paper 3

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The area of the triangle is equal to the area of the trapezium. Calculate the height, h cm, of the trapezium.

Worked Solution & Example Answer:The area of the triangle is equal to the area of the trapezium - OCR - GCSE Maths - Question 15 - 2020 - Paper 3

Step 1

Calculate the area of the triangle

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Answer

The formula for the area of a triangle is given by:

Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}

In this case, the base is 9 cm and the height is 8 cm:

Areatriangle=12×9×8=36 cm2\text{Area}_{triangle} = \frac{1}{2} \times 9 \times 8 = 36\text{ cm}^2

Step 2

Set up the equation for the trapezium

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Answer

The area of a trapezium is calculated using the formula:

Area=12×(Base1+Base2)×height\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{height}

For the given trapezium, the bases are 12 cm and 20 cm, and the height is h cm:

Areatrapezium=12×(12+20)×h=12×32×h=16h cm2\text{Area}_{trapezium} = \frac{1}{2} \times (12 + 20) \times h = \frac{1}{2} \times 32 \times h = 16h\text{ cm}^2

Step 3

Equate the areas of the triangle and the trapezium

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Answer

Since the area of the triangle is equal to the area of the trapezium, we can set up the equation:

36=16h36 = 16h

Step 4

Solve for h

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Answer

To solve for h, divide both sides of the equation by 16:

h=3616=2.25 cmh = \frac{36}{16} = 2.25\text{ cm}

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