18. (a) Sketch the graph of $y = \cos x + 1$ for $0^{\circ} \leq x \leq 720^{\circ}$ - OCR - GCSE Maths - Question 18 - 2018 - Paper 6
Question 18
18. (a) Sketch the graph of $y = \cos x + 1$ for $0^{\circ} \leq x \leq 720^{\circ}$.
(b) Explain why the equation $\cos x + 1 = 2.7$ has no solutions.
Worked Solution & Example Answer:18. (a) Sketch the graph of $y = \cos x + 1$ for $0^{\circ} \leq x \leq 720^{\circ}$ - OCR - GCSE Maths - Question 18 - 2018 - Paper 6
Step 1
Sketch the graph of $y = \cos x + 1$ for $0^{\circ} \leq x \leq 720^{\circ}$
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Answer
To sketch the graph of the function y=cosx+1, we start by recognizing key features of the cosine function:
Basic Shape: The cosine function oscillates between -1 and 1; therefore, cosx+1 will oscillate between 0 and 2.
Period: The standard period of cosx is 360∘, so the behavior of the graph will repeat itself after each 360∘. Hence, when sketching for 0∘≤x≤720∘, we will sketch two full cycles.
Key Points:
At 0∘, y=cos(0)+1=1+1=2.
At 90∘, y=cos(90)+1=0+1=1.
At 180∘, y=cos(180)+1=−1+1=0.
At 270∘, y=cos(270)+1=0+1=1.
At 360∘, y=cos(360)+1=1+1=2.
The same points repeat at x=360∘ and x=720∘.
Graphing: Start the graph at (0,2) and follow the points derived above, ensuring that the curve is smooth, reaches its maximum at x=0∘, 360∘, and has a minimum at 180∘.
Labeling: Clearly label the x-axis and y-axis with appropriate values, ensuring the range of y covers 0 to 2 accordingly.
Step 2
Explain why the equation $\cos x + 1 = 2.7$ has no solutions.
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Answer
The equation cosx+1=2.7 can be rewritten as cosx=2.7−1=1.7.
Range of Cosine: The cosine function, cosx, has a maximum value of 1 and a minimum value of -1. Thus, it cannot equal any value greater than 1 or less than -1.
Conclusion: Since 1.7 exceeds the maximum value of cosx, the equation cosx+1=2.7 has no solutions.